* When the σ is known, za/2 no matter what the sample size is, as long as the variable is normally distributed or n ≥ 30.
* When σ is unknown and n ≥ 30, s can be used in the formula and za/2 values can be used.
* When σ is unknown and n< 30, s is used in the formula and ta/2 values are used, as long as the variable is approximately normally distributed.
* Example for finding the degree of freedom:
(Degree of freedom are the numbers that are free to vary after a sample statistics has been computed, and they tell the researcher which specific curve to use when a distribution consists of a family of curves.)
-Find the ta/2 value for 90% confidence interval when the sample size is 16.
Solution: d.f = 16-1=15. find 15 in the left column and 90% in row labeled confidence intervals. The intersection where the two meets gives the value for ta/2, which is 1.753
*Example for finding the confidence interval of the mean where the given are mean = 0.46,d.f = 14, ta/2 = 1.761, and s = 0.06.
Solution:
0.46 - (1.761)(o.o6/ square root of 15) < mean < 0.46 + (1.761)(o.o6/ square root of 15)
0.46 - 0.027 < mean < 0.46 + 0.27
0.43 < mean < 0.49
Trough the examples that our teacher gave, we have very well understand the concept about finding the confidence interval for the mean (σ is known or n is < 30).
By: Dustin Joshua Esquia
III-Gold
No comments:
Post a Comment